AND only turns TRUE when every argument inside it does, and one of those arguments here is itself an OR — so a request can satisfy either of two routes and still has to clear the tenure rule on top.
You run tuition reimbursement requests for HR at a mid-size firm. The policy: an employee qualifies if they have been employed at least 12 months, and the course is either job-related or was pre-approved by their manager — tenure is never waived, but either of the other two is enough on its own. In E2, work out each request in column E as "Eligible" or "Not eligible", then copy down to row 6.
Solve without hints for +5 XP
This is the grid you start with. Cell references in the task — B6, C2 — point at the row numbers and column letters below.
| A | B | C | D | E | |
|---|---|---|---|---|---|
| 1 | Employee | Months employed | Job-related | Manager pre-approved | Eligible |
| 2 | Alders | 18 | Yes | No | |
| 3 | Brandt | 6 | Yes | Yes | |
| 4 | Corwin | 24 | No | No | |
| 5 | Delgado | 15 | No | Yes | |
| 6 | Ekstrom | 9 | No | Yes |
AND only returns TRUE when both of its arguments do, and its second argument here is OR(C2="Yes",D2="Yes") — which is itself TRUE the moment either half is. That is why Brandt, six months in with both the job-related and pre-approved boxes checked, still comes back Not eligible: the OR clears easily, but AND's other argument, the tenure check, does not, and AND cannot pass on one true argument alone. Delgado is the mirror case — a course that is neither job-related nor pre-approved by itself, but fifteen months of tenure plus manager approval is enough to clear the OR, and with tenure already satisfied that is all AND needs. Flattening this into a single OR of three conditions would have reimbursed Brandt's course on day one, which is exactly what the tenure rule exists to prevent.