Take out the two extremes before averaging, the way judging panels do.
Six judges scored a performance and one of them was wildly out of line. In B9 give the average with the single highest and single lowest score removed.
Solve it on your own to keep the bonus. Each hint gets one step closer to the formula.
The same formula in the other shapes it takes at work.
The mean is a fair summary only when nothing in the data is extreme.
Take out the two extremes before averaging, the way judging panels do.
The typical value for one group, ignoring the small cases.
This is the grid you start with. Cell references in the task — B6, C2 — point at the row numbers and column letters below.
| A | B | |
|---|---|---|
| 1 | Judge | Score |
| 2 | J1 | 8.4 |
| 3 | J2 | 8.1 |
| 4 | J3 | 3 |
| 5 | J4 | 8.6 |
| 6 | J5 | 8.2 |
| 7 | J6 | 9.1 |
| 8 | ||
| 9 | Trimmed average |
One judge's 3.0 pulls the plain average down to 7.57, below five of the six scores. Dropping one score from each end leaves an average of the scores that agree, 8.33, which is why panels and many surveys do exactly this.