The same spread as VAR, back in units you can read.
The same five lead times. Put their standard deviation in B7 — this time the answer comes back in days.
Solve without hints for +5 XP
This is the grid you start with. Cell references in the task — B6, C2 — point at the row numbers and column letters below.
| A | B | |
|---|---|---|
| 1 | Month | Lead time (days) |
| 2 | January | 9 |
| 3 | February | 14 |
| 4 | March | 7 |
| 5 | April | 16 |
| 6 | May | 4 |
| 7 | Standard deviation |
The variance was 24.5 days-squared; the standard deviation is its square root, about 4.95 days. That is a number you can put in a sentence: lead times average 10 days, give or take about 5. For data that clusters around its mean, roughly two thirds of values fall within one standard deviation of it, so this is realistically a 5-to-15 day supplier — a very different thing to promise a customer than 10.